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-5x^2+132x=0
a = -5; b = 132; c = 0;
Δ = b2-4ac
Δ = 1322-4·(-5)·0
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17424}=132$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-132}{2*-5}=\frac{-264}{-10} =26+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+132}{2*-5}=\frac{0}{-10} =0 $
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